Re: Take out one Data and show it in page

From: Date: Thu, 29 Mar 2001 06:16:05 +0000
Subject: Re: Take out one Data and show it in page
References: 1  Groups: php.db 
Request: Send a blank email to php-db+get-7959@lists.php.net to get a copy of this message
Hi, hte first part after WHERE is the column name of your db. if you want to search with name as a criteria you write: selelct name, nickname from table where name=$name; johannes "Naga Sean" <nagasea@kaskus.com> schrieb im Newsbeitrag news:20010329032314.0678136F9@sitemail.everyone.net... > I had a question here. > How to pull up one database, and then view that row > what I mean here is > > NO NAME AGE > 1 JOHN 12 > 2 RYAN 23 > 3 JIM 42 > > I want to take JOHN out from database using URL > www.example.com/template.php?name=JOHN > > here is my coding so far, and I know it's wrong, But will make you guys had the idea what I want to do. > Thanks > > ----------------------------------- > > <?php > $db = mysql_connect("localhost", "user","pass"); > mysql_select_db("media",$db); > $result = mysql_query("SELECT nickname,name FROM database WHERE $myrow[2]=$name",$db); > $myrow = mysql_fetch_row($result); > ?> > > > Your name $myrow[name], $myrow[age] > > _____________________________________________________________ > www.kaskus.com - FREE EMAIL SERVICE > > -- > PHP Database Mailing List (http://www.php.net/) > To unsubscribe, e-mail: php-db-unsubscribe@lists.php.net > For additional commands, e-mail: php-db-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >

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