Can't get my head around this problem...

Hello all... I've got what is probably a stupid question, it's a problem I can't seem to get my head around it. Any help will be greatly appreciated. I'm pulling a count of connections from a MySQL database and the day of the week it occurred on. Now the result set doesn't include empty values, so if there were connections on only 2 days, I only get 2 rows returned, if there were connections on 4 days, I get 4 rows returned. You get the idea... Here is the PHP code I am using the get the data: $sql = "SELECT COUNT(*), (DAYOFWEEK(dialer_login_date) -1) AS DAYOFWEEK FROM dialer_login WHERE dialer_id = $dialer_id AND WEEK(date_format(dialer_login_date, '%Y-%m-%d'),0) = WEEK('$last_week',0) GROUP BY DAYOFWEEK"; $result = db_query($sql); while ($daily_count = db_fetch_array($result)) { $lastweek[] = $daily_count["COUNT(*)"]; $day[] = $daily_count["DAYOFWEEK"]; } For the sake of this question, let's say that there were connections on only 2 days, so we get a result set with 2 rows. Something like this: COUNT(*) DAYOFWEEK 8 2 3 4 That's great, but I need the array $lastweek to have the value 8 in element 2 and the value 3 in element 4 and all other elements (0,1,3,5,6) as zero. As it sits, they are in elements 0 and 1 respectively. I get this: $lastweek[] = 8,3 I need this: $lastweek[] = 0,0,8,0,3,0,0 Now I've written all manner of wild and wonderful loops that iterate through either $lastweek or $day and try and build a proper array. Invariably something doesn't work right. I'm sure I'm grossly over complicating this, but I am at my wits end. Any thoughts or ideas are most welcome. Thanks!! Tyrone Mills ____________________________________________________ UNIX is user-friendly, it's just picky about who its friends are...