RE: [PHP-DB] PHP problem
| From: | Steve Brett | Date: | Mon, 30 Apr 2001 08:43:00 +0000 |
| Subject: | RE: [PHP-DB] PHP problem | ||
| Groups: | php.db | ||
| Request: | Send a blank email to php-db+get-8983@lists.php.net to get a copy of this message | ||
user something like this:
the thing you're looking for is the SELECTED bit of the select drop down ...
echo '<select name="month"
onChange="document.thisForm.submit()">';
$months = Array("January", "February", "March", "April",
"May", "June",
"July", "August", "September", "October",
"November", "December");
for ($x=1; $x <= count($months); $x++)
{
print "\t<option value=\"$x\" ";
print ($x == intval($cmonth)) ? " SELECTED":" ";
print ">".$months[$x-1]."\n</option>";
}
echo ' </select> ';
get the form to submit itself using action=<?php print $PHP_SELF() ?>
Steve
> -----Original Message-----
> From: Johan [mailto:heegs800@man.nhl.nl]
> Sent: 29 April 2001 16:02
> To: php-db@lists.php.net
> Subject: [PHP-DB] PHP problem
>
>
> Dear Sir/Madam,
>
> I have a mysql database available with user information. I want that
> visitors have the change to change their personel
> information. Now the form
> works with two different types of fields. edit-fields and
> selectie/option-lists.
>
> How do I get the value of a user from a selectionlists selected in the
> form-field. All options must be availabele, but the value of
> the user must
> be selected in the form field.
>
> If anyone can help me please mail me at heegs800@man.nhl.nl
>
> Thanks
>
> Johan.
>
>
>
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