PHP 4.0 Bug #2692 Updated: clarification: unset and reference
| From: | Bug Database | Date: | Sun, 14 Nov 1999 08:02:07 +0000 |
| Subject: | PHP 4.0 Bug #2692 Updated: clarification: unset and reference | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-12483@lists.php.net to get a copy of this message | ||
ID: 2692
Updated by: joey
Reported By: php-bug@vogtner.de
Status: Open
Bug Type: Misbehaving function
Assigned To:
Comments:
${$v} should work for a dereference operator, right?
If you compare the output of the script below with that
of the original example above, you will see that "dereferencing"
unset($v) is no longer breaking the reference...
Moving to "Misbehaving function". unset() should not break
ref.
<?
function sub (&$v)
{
unset (${$v});
$v = 66;
}
sub ($s);
echo '<br>$s = '. $s . "\n";
echo '<br>isset ($s) = '. isset ($s) . "\n";
?>
Full Bug description available at: http://bugs.php.net/version4/?id=2692