PHP 4.0 Bug #2852: argv/argc inconsistency while running as command-line script

From: stas@zend.com Operating system: Linux PHP version: 4.0 Beta 3 PHP Bug Type: Scripting Engine problem Bug description: argv/argc inconsistency while running as command-line script Following script (argv.php3): #!/usr/bin/php -f <? printf("argc: %d\nargv1-2:%s-%s\n",$argc,$argv[0],$argv[1]); ?> when run as ./argv.php3 (without parameters), says: argc: 1 argv1-2:- when run as ./argv.php3 abc (1 parameter), says: argc: 1 argv1-2:abc- Shouldn't argc be different in two cases? When I do not put -f, script name is included in argv and argc is OK. Same effects if I run php -f argv.php3 (like the first case) and php argv.php3 (like the second case).