Bug #1585 Updated: Arrays & scalar variables of same name cant coexist

From: Date: Sat, 12 Feb 2000 21:58:04 +0000
Subject: Bug #1585 Updated: Arrays & scalar variables of same name cant coexist
Groups: php.dev 
Request: Send a blank email to php-dev+get-15476@lists.php.net to get a copy of this message
ID: 1585 Updated by: torben Reported By: al52x@nih.gov Status: Closed Bug Type: Documentation problem Assigned To: Comments: There is now a note in the docs about this, but the code below isn't doing quite what you think and so you're hitting this problem. Background: the behaviour of implicit conversion between array and string types using [] is undefined. For instance: <?php $a = "This is a test"; $a[0] = 'X'; echo $a; // should this work? ?> In this example, should 'echo $a' produce 'Xhis is a test', or 'Array'? The assignment (knowing that $a is a string) could mean either. This applies to your example because when you run this: /* imtg1 is an integer here: */ $imtg1=mysql_Result($res,0,"mtg1"); ...$imtg1 is *not* an integer; it's a string holding a numeric value. Apparently, it's only 3 chars long, so when you attempt to assign to $imtg1[3], you've gone off the end of the string. The easiest workaround is simply to use another variable there. Full Bug description available at: http://bugs.php.net/?id=1585

« previous php.dev (#15476) next »