Re: What is 'var'

j>> Hmm, but my point was that I could do that without the word 'var'. j>> j>> The word 'var' seems to have no reason for its existence, for instance, j>> this should work (but doesn't). j>> class foo { j>> $foo_var = 0; j>> } You could omit word 'class' too. And { } and = and ; are optional. Like this: foo: foo_far 0 foo_func($a) a + a b Doesn't this remind you those lovely assembler days? ;) Seriaously, var allows you (and parser) to distinguish class initializers from some assignment left out of some function. -- Stanislav Malyshev stas@zend.com +972-3-6139665