PHP 4.0 Bug #5614: Access Violation

From: Date: Sat, 15 Jul 2000 03:10:26 +0000
Subject: PHP 4.0 Bug #5614: Access Violation
Groups: php.dev 
Request: Send a blank email to php-dev+get-24614@lists.php.net to get a copy of this message
From: mbeers@udeco.com Operating system: Windows 2000 PHP version: 4.0 Release Candidate 2 PHP Bug Type: MSSQL related Bug description: Access Violation I am using the Win32 binaries, downloaded on July 14. The error I get is: PHP has encountered an Access Violation at 0150229E. It occurs when I use the mssql_close() function without a link identifier. This is the code which causes the break: <? mssql_connect($SERVER_NAME, $USER_ID, $DB_PASSWORD) or die("unable to connect to server"); mssql_select_db($DB_NAME) or die("unable to connect to db"); $result = mssql_query("select field1, field2 from TestPHP where field1 > 1"); print "num rows=" . mssql_num_rows($result) . "<br>"; while ($data = mssql_fetch_row($result)) { print "field1=$data[0], field2=$data[1]<br>"; } mssql_close(); ?> If I store the link identifier when I call the connect statement ($link = mssql_connect), and pass that link identifier in when I call close (mssql_close($link), all is well. Finally, it happens with any sql statement I execute. Thank you for your hard work.

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