PHP 4.0 Bug #5614: Access Violation
| From: | mbeers at udeco dot com | Date: | Sat, 15 Jul 2000 03:10:26 +0000 |
| Subject: | PHP 4.0 Bug #5614: Access Violation | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-24614@lists.php.net to get a copy of this message | ||
From: mbeers@udeco.com
Operating system: Windows 2000
PHP version: 4.0 Release Candidate 2
PHP Bug Type: MSSQL related
Bug description: Access Violation
I am using the Win32 binaries, downloaded on July 14.
The error I get is:
PHP has encountered an Access Violation at 0150229E.
It occurs when I use the mssql_close() function without a link identifier. This is the code which
causes the break:
<?
mssql_connect($SERVER_NAME, $USER_ID, $DB_PASSWORD) or die("unable to connect to server");
mssql_select_db($DB_NAME) or die("unable to connect to db");
$result = mssql_query("select field1, field2 from TestPHP where field1 > 1");
print "num rows=" . mssql_num_rows($result) . "<br>";
while ($data = mssql_fetch_row($result)) {
print "field1=$data[0], field2=$data[1]<br>";
}
mssql_close();
?>
If I store the link identifier when I call the connect statement ($link = mssql_connect), and pass
that link identifier in when I call close (mssql_close($link), all is well.
Finally, it happens with any sql statement I execute.
Thank you for your hard work.