Re: RE: PHP 4.0 Bug #6193 Updated: new object makes a shallow copy

At 11:31 PM 8/18/00 +0200, André Langhorst wrote:

You should think of "$a =& $b;" as "make the symbol table entry $a reference the same PHP value bucket as $b. If the $a symbol table entry was in use before it just changes it to point at the same PHP value bucket as $b. It is a symbol table re-assign.

As stated before I´m aware of the problem, OTOH I see how a php-dev expects it to be... couldn´t you invent a kind of biometric identification or quantum signature? ;)

Nope :) Let's just not call it references and call it aliasing :) Andi --- Andi Gutmans <andi@zend.com> http://www.zend.com/