What *should* happen is the second array item (b) should disappear. What
*does* happen is that $dope[1] is unset, AND the index is reduced, but the
item isn't deleted. So your array now goes "a", (blank), "c", "d". Both
"b" and "e" were lost.
PHP always uses associative arrays -- so performing unset() on an array
index leaves you with the proper number of elements. Your array just no
longer contans the key 1 when you do the above.
well that was he was worried about, that this did *not* happen
the way you described