PHP 4.0 Bug #7453 Updated: echo still not handling double scripted arrays

ID: 7453 Updated by: joey Reported By: pwoneill@email.com Status: Closed Bug Type: *General Issues Assigned To: Comments: I'm not sure why Jim said that. I've never seen this work any other way...it's just a know limitation. Instead do: $tmp = $array[0]["somekey"]; print $tmp; I doubt this will change soon. Previous Comments: --------------------------------------------------------------------------- [2000-10-25 12:12:09] pwoneill@email.com This was originally posted in Bug #1859, which is closed, saying it was fixed in PHP 4.0, but I have been having a similar problem Example Code: --------------------- <?php $people = array( array("Name" => "Bill", "Age" => "20"), array("Name" => "Bob", "Age" => "30") ); echo ("using echo embedded, $people[0][Name]n"); echo ("using echo non-embedded, " . $people[0][Name] . "n"); printf("using printf, %sn", $people[0][Name]); ?> Output: ------------------------- using echo embedded, Array[Name] using echo non-embedded, Bill using printf, Bill It seems the variables-in-quotes expansion isn't working at least in this case of PHP 4.0.3pl1. --------------------------------------------------------------------------- Full Bug description available at: http://bugs.php.net/?id=7453