PHP 4.0 Bug #7578: next() and current() do not return referenceing arrays

From: Date: Thu, 02 Nov 2000 00:29:27 +0000
Subject: PHP 4.0 Bug #7578: next() and current() do not return referenceing arrays
Groups: php.dev 
Request: Send a blank email to php-dev+get-36727@lists.php.net to get a copy of this message
From: mog@linux.nu Operating system: RedHat Linux 7 PHP version: 4.0.1pl2 PHP Bug Type: Arrays related Bug description: next() and current() do not return referenceing arrays i hope you can see what is wrong in the code below <?PHP $array2 = array(0,1,2); $array = array(&$array2); print current(current($array))."<br>"; // returns 0 print "<b>Try 1!</b><br>"; print next(current($array))."<br>"; // returns 1, correct but the internal pointer is only moved in the copy current() returned print current(current($array))."<br>"; // returns 0, wrong, should be 1 print current($array2)."<br>"; //returns 0, wrong, should be 1 print "<b>Try 2!</b><br>"; print next($array[0])."<br>"; print current(current($array))."<br>"; // returns 0, wrong, should be 1 print current($array[0])."<br>"; // returns 1, yes, correct! but the code above still didn't work! ?> -- Edit Bug report at: http://bugs.php.net/?id=7578&edit=1

« previous php.dev (#36727) next »