RE: [PHP-DEV] PHP 4.0 Bug #7592: LIKE operator fails
| From: | Daniel J. Rodriguez | Date: | Thu, 02 Nov 2000 21:01:35 +0000 |
| Subject: | RE: [PHP-DEV] PHP 4.0 Bug #7592: LIKE operator fails | ||
| References: | 1 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-36840@lists.php.net to get a copy of this message | ||
For a simple reason:
Access makes use of different characters for pattern matching than
ANSI SQL does. Try replacing * with % and see what the result is.
If you are also using ?, you should replace it with _
Regards
Daniel
----- Original Message -----
From: <frederic.choquet@caramail.com>
To: <php-dev@lists.php.net>
Sent: Thursday, November 02, 2000 4:09 PM
Subject: [PHP-DEV] PHP 4.0 Bug #7592: LIKE operator fails
> From: frederic.choquet@caramail.com
> Operating system: WinNT 4.0 WS
> PHP version: 4.0.3pl1
> PHP Bug Type: ODBC related
> Bug description: LIKE operator fails
>
> It seems impossible to use the SQL "LIKE" operator with ODBC/ACCESS
97.
>
> ie:
> $sqlstring = "SELECT Name FROM people WHERE Name LIKE \"A*\"";
> $rst=odbc_exec($Conn, $sqlstring);
>
> ... may return the following err msg:
>
> Impossible d'utiliser cette expression avec le prédicat LIKE. dans
l'expression 'Name alike
A*'
>
> (sorry, it's in french, in english it may look like: Unable to use
this expression with operator LIKE in expression 'Name alike A*')
>
> What does this "alike" means?
>
> If i echo $sqlstring, cut it and paste it directly to a query in
Access, i got no err msg, so it is not a syntax error.
>
>
> --
> Edit Bug report at: http://bugs.php.net/?id=7592&edit=1
>
>
>
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