Bug #1099: Strange behaviour of regular expressions

From: thifi@telnet.hu Operating system: Linux, Debian Slink, 2.2.0 PHP version: 3.0.6 PHP Bug Type: Misbehaving function Bug description: Strange behaviour of regular expressions There is the following line in a text file: 1.word ##test,hello### 2.word 3.word ##test2,hello###, 4.word! I'd like to replace every ##...### enclosed characters with a string: In perl it works like this: #!/usr/bin/perl open(F,"<test.txt"); while(<F>) { chomp; s/##.*?,.*?###/REPLACED/g; print "$_\n"; } close(F); output: # ./test.pl 1.word REPLACED 2.word 3.word REPLACED, 4.word! But in php3: #!/usr/lib/cgi-bin/php3 -q <? $file = fopen("test.txt","r"); while(!feof($file)) { $s = chop(fgets($file,10000)); $s = ereg_replace("##.*?,.*?###","REPLACED",$s); echo("$s\n"); } fclose($file); ?> output is: # ./test.php3 1.word REPLACED, 4.word! So why can't I use .*? in a regular expression function? If I made a mistake then sorry for the report. -- PHP Development Mailing List http://www.php.net/ To unsubscribe send an empty message to php-dev-unsubscribe@lists.php.net For help: php-dev-help@lists.php.net