Re: PHP 4.0 Bug #7985 Updated: All PHP 3 scripts have "Undefined Variable" Warnings

From: Date: Mon, 27 Nov 2000 05:15:52 +0000
Subject: Re: PHP 4.0 Bug #7985 Updated: All PHP 3 scripts have "Undefined Variable" Warnings
References: 1  Groups: php.dev 
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Thanks, after examining the php.ini file further I was able to supress the warnings. Signed Richard Lacroix CLP, BSc mailto:richlacroix@home.com ----- Original Message ----- From: "Bug Database" <php-dev@lists.php.net> To: <richlacroix@home.com> Sent: Sunday, November 26, 2000 9:36 PM Subject: PHP 4.0 Bug #7985 Updated: All PHP 3 scripts have "Undefined Variable" Warnings > ID: 7985 > Updated by: rasmus > Reported By: richlacroix@home.com > Status: Closed > Bug Type: MySQL related > Assigned To: > Comments: > > Those are very valid warnings. You get them in PHP 3 as well if you set your error_reporting level high enough. If you don't want to see these warnings change your error_reporting level in your php.ini file. > > Previous Comments: > -------------------------------------------------------------------------- - > > [2000-11-26 21:24:34] richlacroix@home.com > Running the PHP tutorial on the latest Apache build with the latest MySQL available (all for win 32k) the example scripts that were written for PHPv3 always come back with Warning: Undefined variable, i.e. > Warning: Undefined variable: submit in d:program filesapache groupapachehtdocsmysqltest.php on line 21 > > Warning: Undefined variable: delete in d:program filesapache groupapachehtdocsmysqltest.php on line 41 > > Warning: Undefined variable: id in d:program filesapache groupapachehtdocsmysqltest.php on line 55 > from the following script (taken from the tutorial located at: > http://hotwired.lycos.com/webmonkey/99/21/index2a.html ) > > Script: > <html> > > > > <body> > > <?php > > > > $db = mysql_connect("localhost", "Web User"); > > mysql_select_db("mydb",$db); > > > > if ($submit) { > > // here if no ID then adding else we're editing > > if ($id) { > > $sql = "UPDATE employees SET first='$first',last='$last',address='$address',position='$position' WHERE id=$id"; > > } else { > > $sql = "INSERT INTO employees (first,last,address,position) VALUES ('$first','$last','$address','$position')"; > > } > > // run SQL against the DB > > $result = mysql_query($sql); > > echo "Record updated/edited!<p>"; > > } elseif ($delete) { > > // delete a record > > $sql = "DELETE FROM employees WHERE id=$id"; > > $result = mysql_query($sql); > > echo "$sql Record deleted!<p>"; > > } else { > > // this part happens if we don't press submit > > if (!$id) { > > // print the list if there is not editing > > $result = mysql_query("SELECT * FROM employees",$db); > > while ($myrow = mysql_fetch_array($result)) { > > printf("<a href="%s?id=%s">%s %s</a> n", $PHP_SELF, > $myrow["id"], $myrow["first"], $myrow["last"]); > > printf("<a > href="%s?id=%s&delete=yes">(DELETE)</a><br>", $PHP_SELF, $myrow["id"]); > > } > > } > > > > ?> > > <P> > > <a href="<?php echo $PHP_SELF?>">ADD A RECORD</a> > > <P> > > <form method="post" action="<?php echo $PHP_SELF?>"> > > <?php > > > > if ($id) { > > // editing so select a record > > $sql = "SELECT * FROM employees WHERE id=$id"; > > $result = mysql_query($sql); > > $myrow = mysql_fetch_array($result); > > $id = $myrow["id"]; > > $first = $myrow["first"]; > > $last = $myrow["last"]; > > $address = $myrow["address"]; > > $position = $myrow["position"]; > > // print the id for editing > > > > ?> > > <input type=hidden name="id" value="<?php echo $id ?>"> > > <?php > > } > > > > ?> > > First name:<input type="Text" name="first" value="<?php echo > $first ?>"><br> > > Last name:<input type="Text" name="last" value="<?php echo > $last ?>"><br> > > Address:<input type="Text" name="address" value="<?php echo > $address ?>"><br> > > Position:<input type="Text" name="position" value="<?php echo > $position ?>"><br> > > <input type="Submit" name="submit" value="Enter > information"> > > </form> > > > > <?php > > > > } > > > > ?> > > > > </body> > > </html> > > I'm new to PHP, but not development, I've checked the script against every bit of documentation I could find - spending an entire day doing so, but I can't understand why this is happening - according to everything I've seen so far, this should not be happening. > Please advise. > Thanks > Richard > P.S. Simple scripts work fine, as long as I don't try anything like a $submit, $delete, and so on from a form. > > -------------------------------------------------------------------------- - > > > Full Bug description available at: http://bugs.php.net/?id=7985 >

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