PHP 4.0 Bug #8115 Updated: variable passed by reference incorrectly handled

ID: 8115 Updated by: stas Reported By: christian@architech.no Status: Closed Bug Type: Scripting Engine problem Assigned To: Comments: This is exactly as it is meant to work. Please read "References explained" in the manual. When you do the unset, you effectively destroy local variable $a, breaking the reference. Now when you mention $a again, it's not referenced to $my_var anymore - it's a new variable. Previous Comments: --------------------------------------------------------------------------- [2000-12-05 06:27:46] christian@architech.no It concerns variables passed by reference... and the unset() function. # Let's define a very simple function that converts an array to a string : function foo(&$a) { $an_array = array("abcdef"); unset($a); for ($i=0; $i<sizeof($an_array); $i++) $a = $a . $an_array[$i]; } # and call it : foo($my_var); # $my_var is NOT EQUAL TO "abcdef" !!!!! However it works fine when we don't try to unset the $a variable. (replacing the line with $a = ""). --------------------------------------------------------------------------- Full Bug description available at: http://bugs.php.net/?id=8115