PHP 4.0 Bug #8139 Updated: NULL and isset
| From: | joey@php.net | Date: | Wed, 06 Dec 2000 18:18:04 +0000 |
| Subject: | PHP 4.0 Bug #8139 Updated: NULL and isset | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-40237@lists.php.net to get a copy of this message | ||
ID: 8139
Updated by: joey
Reported By: richard.heyes@heyes-computing.net
Status: Feedback
Bug Type: Scripting Engine problem
Assigned To:
Comments:
The question is: should passing an unset variable by reference
generate a warning?
Previous Comments:
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[2000-12-06 12:57:39] richard.heyes@heyes-computing.net
<?php
function foo(&$bar){
return TRUE;
}
foo($bar);
print($bar);
if(!isset($bar))
print('Bar is not set!');
?>
With notices turned on (error_reporting) the call to print($bar) does not throw an error. However
the bit below it runs the print() call. So if it's not set, the first print should throw an
error regarding the unset $bar. Seems very contradictory. FWIW the type of $bar after the call to
foo() is NULL.
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Full Bug description available at: http://bugs.php.net/?id=8139