Bug #1140: bn=language-parser.tab.o: Command not found.
| From: | vanek at czu dot cz | Date: | Thu, 11 Feb 1999 12:03:15 +0000 |
| Subject: | Bug #1140: bn=language-parser.tab.o: Command not found. | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-4037@lists.php.net to get a copy of this message | ||
From: vanek@czu.cz
Operating system: IRIX 6.4 IP27
PHP version: 3.0.6
PHP Bug Type: Compile Failure
Bug description: bn=language-parser.tab.o: Command not found.
When I try to compile PHP and apache v.1.3.4 with mysql I found a compiling error in the folowing
statement:
Step 1:
cd apache_1.3.4
./configure --prefix=/<localpath>
result: OK
Step 2:
cd ../php-3.0.x
./configure --with-mysql --with-apache=../apache_1.3.4 --enable-track-vars
result: OK
Step 3:
make
result:
gcc -g -O2 -O2 -I. -I. -I../apache_1.3.4/src/include -I../apache_1.3.4/src/os/unix
-I/usr/local/include/mysql <...>
bn=language-parser.tab.o: Command not found.
*** Error code 1 (bu21)
----
list from Makefile:
.c.o:
$(CC) $(CFLAGS) -c $< -o $@
@bn=
echo $@ | sed -e 's#functions/##'; test -f $@ || \
(test "$@" != "$$bn" && test -f "$$bn" && mv
$$bn $@)
functions/number.o: functions/number.c
$(CC) $(CFLAGS) -w$(WARNING_LEVEL) -c $< -o $@
@bn=echo $@ | sed -e 's#functions/##'; test -f $@ || \
(test "$@" != "$$bn" && test -f "$$bn" && mv
$$bn $@)
----
I think the problem is with @bn=`... , but I don't know how to solve it. Please, would you be
so kind as to help me?
Thanks,
JV (vanek@czu.cz)
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