PHP 4.0 Bug #8299: xsl:include doesn't work

From: Date: Sat, 16 Dec 2000 23:58:52 +0000
Subject: PHP 4.0 Bug #8299: xsl:include doesn't work
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From: jpoon88@yahoo.com Operating system: RedHat Linux PHP version: 4.0.3pl1 PHP Bug Type: Sablotron XSL Bug description: xsl:include doesn't work We encountered an error when using "xsl:include" syntax. It always return "error no: 242 " when I transform my xml file with my xsl file. I use the same file with MS XML Parser 3.0, it work okay. I confirmed with Tom Kaiser that xsl:include is supported in 0.43, but it's definitely better to upgrade to 0.44 (and to 0.5 when it's out finally). Here is the listing of the files for your testing: XSL file: test.xsl ------------------ <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html"/> <xsl:include href="test2.xsl"/> <xsl:template match="/"> <html><head>This is header</head> <body> <xsl:apply-templates select="node()"/> </body> </html> </xsl:template> </xsl:stylesheet> XSL file: text2.xsl ------------------- <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:template match="bold"> <P><B><xsl:value-of select="."/></B></P> </xsl:template> <xsl:template match="red"> <P style="color:red"><xsl:value-of select="."/></P> <p> Testing</p> </xsl:template> <xsl:template match="italic"> <P><i><xsl:value-of select="."/></i></P> </xsl:template> </xsl:stylesheet> XML File: data.xml ------------------ <?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="test.xsl"?> <xslTutorial> <bold>Hello, world.</bold> <red>I am </red> <italic>fine.</italic> </xslTutorial> What's meaning of the error code 204? Anyone have similar problem???? -- Edit Bug report at: http://bugs.php.net/?id=8299&edit=1

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