PHP 4.0 Bug #8290 Updated: allow func_*_arg?() functions as function parameters inside a function

ID: 8290 Updated by: waldschrott Reported By: cynic@mail.cz Status: Analyzed Bug Type: Feature/Change Request Assigned To: Comments: I thought of something like INTERNAL_PARAM_PASSTHROUGH, otherwise you would have to do bar(fung_get_arg(0),func_get_arg(1),func_get_arg(2)...) or bar(func_get_args()) and then in bar work with an array of args Previous Comments: --------------------------------------------------------------------------- [2000-12-18 08:35:48] cynic@mail.cz no need for constants - func_get_arg() / func_get_args() does that. --------------------------------------------------------------------------- [2000-12-16 14:31:56] waldschrott@php.net agreed, maybe even (as a special case in function calls) some constant containing the desired argument from function1 eg. __arg0, __arg1 but I guess this would be a performance loss anyway using func_get_arg? in function calls makes sense sometimes --------------------------------------------------------------------------- [2000-12-16 02:46:32] cynic@mail.cz It'd be handy if one could do function foo() { ... $x = bar( func_get_arg( 0 ) ) ; ... } --------------------------------------------------------------------------- Full Bug description available at: http://bugs.php.net/?id=8290