Re: PHP 4.0 Bug #8428 Updated: continue doesn't pass thru a switch statement

Forgot to cc the list... Um, I don't know. This looks to me like trying to hide problems/ inconsistencies/bugs too easily. :) I think it should stay in the bug realm. I, just like the other guy, consider this a bug. What good is continue within switch if it's the same as break, while it's clearly (meant to be) something different? It could as well trigger an error: 'use break instead'. At 05:04 6.1. 2001, Zak Greant wrote the following: -------------------------------------------------------------- >I should have read your message more carefully :) > >I have changed the bug report to be a feature request. > > --zak > >Cynic wrote: >> zak, >> >> the problem is if != switch in this context. >> see >> http://marc.theaimsgroup.com/?l=php-dev&m=97875059607513&w=2 >> >> >> >> At 04:33 6.1. 2001, zak@php.net wrote the following: >> -------------------------------------------------------------- >> >ID: 8428 >> >Updated by: zak >> >Reported By: ocomte@guarantycity.com >> >Old-Status: Open >> >Status: Bogus >> >Bug Type: Unknown/Other Function >> >Assigned To: >> >Comments: >> > >> >The switch statement is a flow control construct - like for or if. >Because of this continue behaves within switch like it should in any flow >control contruct - it skips to the next loop of the construct. However, >switch does not loop - so continue behaves like break. >> > >> >If you would like to use a continue embedded in a switch statement to >continue past a loop in an outside control construct, specify how many >levels you would like continue to break out of. >> > >> >Try these examples to see what I mean: >> > >> ><pre> >> ><?php >> > for ($i=0; $i<5; ++$i) >> > { >> > switch(1) >> > { >> > case 1: >> > continue 2; >> > break; >> > } >> > >> > echo "Should be skipped"; >> > } >> > >> > // Should not output anything >> > >> > for ($i=0; $i<5; ++$i) >> > { >> > for ($z=10; $z>5; --$z) >> > { >> > switch(1) >> > { >> > case 1: >> > continue 2; >> > break; >> > } >> > echo "\$z=$z\n"; >> > } >> > echo "\$i=$i\n"; >> > } >> > >> > /* >> > Should output: >> > $i=0 >> > $i=1 >> > $i=2 >> > $i=3 >> > $i=4 >> > */ >> >?> >> > >> > >> > >> > >> >Previous Comments: >> >>--------------------------------------------------------------------------- >> > >> >[2000-12-26 13:34:59] ocomte@guarantycity.com >> >in the script : >> ><? >> > for($i=0; $i<5; ++$i) >> > { switch(1) >> > { case 1: >> > continue; >> > } >> > echo "Not printable"; >> > } >> >?> >> > >> >the string is printed 5 times because the continue statement end the >switch (like break). In C and C++, and in the PHP manual the continue >(unlike break) isn't affected by surrounding switch statement and it seems >logical to me. >> > >> > >> >>--------------------------------------------------------------------------- >> > >> > >> >Full Bug description available at: >> >http://bugs.php.net/?id=8428 >> > >> > >> >-- >> >PHP Development Mailing List >> ><http://www.php.net/> >> >To unsubscribe, e-mail: php-dev-unsubscribe@lists.php.net >> >For additional commands, e-mail: php-dev-help@lists.php.net >> >To contact the list administrators, e-mail: php-list-admin@lists.php.net >> ------end of quote------ >> >> >> >> ____________________________________________________________ >> Cynic: >> >> A member of a group of ancient Greek philosophers who taught >> that virtue constitutes happiness and that self control is >> the essential part of virtue. >> >> cynic@mail.cz >> >> ------end of quote------ ____________________________________________________________ Cynic: A member of a group of ancient Greek philosophers who taught that virtue constitutes happiness and that self control is the essential part of virtue. cynic@mail.cz