PHP 4.0 Bug #8336 Updated: Won't compile

ID: 8336 Updated by: sniper Reported By: tim@timmy.org Old-Status: Open Status: Closed Bug Type: Compile Failure Assigned To: Comments: This should be fixed in CVS. Please try the latest snapshot from http://snaps.php.net/ --Jani Previous Comments: --------------------------------------------------------------------------- [2000-12-20 10:35:04] tim@timmy.org Hi, I'm having a problem compiling php. When I configure it using this: ./configure --with-zeus=/usr/local/zeus --without-gd --without-mysql --with-sybase-ct=/usr/local/sybase/OCS-12_0 --enable-libgcc --disable-session --disable-debug and I type make to compile I get this: [root@dbserve php-4.0.4]# make Making all in Zend make[1]: Entering directory `/usr/local/src/php-4.0.4/Zend' /bin/sh ../libtool --silent --mode=compile g++ -DHAVE_CONFIG_H -I. -I. -I../main -D_POSIX_PTHREAD_SEMANTICS -D_POSIX_PTHREAD_SEMANTICS -D_REENTRANT -DXML_BYTE_ORDER=21 -I../TSRM -g -O2 -pthreads -c zend_language_scanner_cc.cc In file included from zend_language_scanner_cc.cc:2571: zend_operators.h: In function `int is_numeric_string(char *, int, long int *, double *)': zend_operators.h:84: implicit declaration of function `int finite(...)' make[1]: *** [zend_language_scanner_cc.lo] Error 1 make[1]: Leaving directory `/usr/local/src/php-4.0.4/Zend' However, if I configure using the exact same as above, except without "--without-mysql", it will compile that file, then I can reconfigure with "--without-mysql", properly... weird --Timmy --------------------------------------------------------------------------- Full Bug description available at: http://bugs.php.net/?id=8336