PHP 4.0 Bug #8582 Updated: normal if nested in alternate if gives parse error
| From: | stas@php.net | Date: | Mon, 08 Jan 2001 11:53:31 +0000 |
| Subject: | PHP 4.0 Bug #8582 Updated: normal if nested in alternate if gives parse error | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-43353@lists.php.net to get a copy of this message | ||
ID: 8582
Updated by: stas
Reported By: wojas@vvtp.nl
Old-Status: Open
Status: Closed
Bug Type: Scripting Engine problem
Assigned To:
Comments:
Indeed the parser thinks else is a part of second construct
and chokes on ":". I'd suggest first to switch to newer {}
syntax, and then bracket your ifs so that you are sure you
and the parser agree on what is the part of what.
Previous Comments:
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[2001-01-07 20:09:41] wojas@vvtp.nl
The following php code gives a parse error at the 'else:'
<?php
if(1==1):
echo "ok so far<p>";
if(1==1) echo "error here!";
else:
echo "Not possible";
endif;
?>
It looks like php thinks the 'else:' is part of the second
if construct; the following code works:
<?php
if(1==1):
echo "ok so far<p>";
if(1==1) echo "error here!";
echo "void";
else:
echo "Not possible";
endif;
?>
Tested with 4.0.3pl1, 4.0.4RC3 and 3.0.18 on debian woody and potato.
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Full Bug description available at: http://bugs.php.net/?id=8582