PHP 4.0 Bug #8860 Updated: variable array not working

ID: 8860 Updated by: stas Reported By: wico@cnh.nl Status: Open Old-Bug Type: Scripting Engine problem Bug Type: Feature/Change Request Assigned To: Comments: It is definitely not meant to work this way. 'test[2]' is not a variable name. $test is the variable (array), and $test[2] is second element of the array. So it belongs to feature requests. Previous Comments: --------------------------------------------------------------------------- [2001-01-23 10:20:59] cynic@php.net ah, sorry, should've read the report more carefully. --------------------------------------------------------------------------- [2001-01-23 10:07:21] wico@cnh.nl changed status --------------------------------------------------------------------------- [2001-01-23 10:06:24] wico@cnh.nl ok and that isn;t working either... althoug i liked the first more (and still think it should be that way) so this doesn't work either: $three = "Grrrr"; echo "Test"; $test = Array("one","two","three","four"); $var = 'test[2]'; echo $$var; /* should echo "three" */ --------------------------------------------------------------------------- [2001-01-23 09:59:43] cynic@php.net no. it will echo contents of $three. if you don't have that variable in current scope, it'll echo null, and, depending on your settings, emit a warning. --------------------------------------------------------------------------- [2001-01-23 09:57:18] wico@cnh.nl according to Zeev this should work: $test = Array("one","two","three","four"); $var = 'test[2]'; echo $$var; /* should echo "three" */ But with it doesn't Greetz, Wico --------------------------------------------------------------------------- The remainder of the comments for this report are too long. To view the rest of the comments, please view the bug report online. Full Bug description available at: http://bugs.php.net/?id=8860