PHP 4.0 Bug #1029 Updated: printf (& sprintf) dosn't handle exponential format for floats correctly

ID: 1029 Updated by: jimw Reported By: leif.thuresson@tsl.uu.se Status: Open Bug Type: Feature/Change Request Assigned To: Comments: really reassigned to 4.0 this time. Previous Comments: --------------------------------------------------------------------------- [1999-11-12 11:31:07] joey@cvs.php.net Moving to feature req. --------------------------------------------------------------------------- [1999-01-05 06:29:54] leif.thuresson@tsl.uu.se System: Linux, Apache with PHP-module Problem: printf (& sprintf) dosn't handle exponential format for floats correctly Comment: This isn't actually a bug since it isn't documented to work in the manual. I nedded exponential format in my application and since the function "formatted_print.c" already had some support for exp. format (but not working correctly) the simplest solution was to fix it in the php source code. Below is my patch to "formatted_print.c" if you would like to include it in a future rease of PHP. Thanks for a great tool for building web interfaces to databases ! Regards, -leif *** formatted_print.c.org Mon Jan 4 21:06:38 1999 --- formatted_print.c Mon Jan 4 21:13:09 1999 *************** *** 257,263 **** } else if (precision > MAX_FLOAT_PRECISION) { precision = MAX_FLOAT_PRECISION; } ! cvt = _php3_cvt(number, precision, &decpt, &sign, (fmt == 'e')); if (sign) { numbuf[i++] = '-'; --- 257,266 ---- } else if (precision > MAX_FLOAT_PRECISION) { precision = MAX_FLOAT_PRECISION; } ! if (fmt == 'e') ! cvt = _php3_cvt(number, precision+1, &decpt, &sign, 1); ! else ! cvt = _php3_cvt(number, precision, &decpt, &sign, 0); if (sign) { numbuf[i++] = '-'; *************** *** 288,294 **** while (cvt[j]) { numbuf[i++] = cvt[j++]; } ! numbuf[i] = '