Re: PHP 4.0 Bug #9337 Updated: make in_array return key, if searched value was found

How about using array_keys($array, $value) to find the key? On Mon, 19 Feb 2001, andre@php.net wrote: > ID: 9337 > Updated by: andre > Reported By: sbergmann@php.net > Old-Status: Open > Status: Feedback > Bug Type: Feature/Change Request > Assigned To: > Comments: > > maybe a fourth parameter switch to avoid 0->false problems? > > Previous Comments: > --------------------------------------------------------------------------- > > [2001-02-19 11:18:18] sbergmann@php.net > in_array() currently returns only true/false on whether or not a searched-for value is in a > given array. > > I would like it to return the key of the array's element when value was found, and false > otherwise. This should not break existing code using in_array(). > > > --------------------------------------------------------------------------- > > > > ATTENTION! Do NOT reply to this email! > To reply, use the web interface found at > http://bugs.php.net/?id=9337&edit=2 > > > -- > PHP Development Mailing List <http://www.php.net/> > To unsubscribe, e-mail: php-dev-unsubscribe@lists.php.net > For additional commands, e-mail: php-dev-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net > -Andrei Complexity in the mind is not caused by learning; learning is caused by complexity in the mind. -- Steven Pinker