PHP 4.0 Bug #9414 Updated: date() returns error when included in an object

ID: 9414 Updated by: torben Reported By: eric@lcb.uoregon.edu Old-Status: Open Status: Closed Bug Type: Date/time related Assigned To: Comments: Not a bug; from the manual (http://www.php.net/manual/en/language.oop.php): Note: In PHP 4, only constant initializers for var variables are allowed. Use constructors for non-constant initializers. So you could have 'var $dateTest = "foo";', or 'var $dateTest = 201029;', but not anything which would depend upon runtime evaluation. What this means is that you should have something like this instead: <?php class showDate { var $dateTest; function showDate() { $this->dateTest = date("Y-m-d"); } } ?> This could probably benefit from a better example in the manual, though. Cheers, Torben Previous Comments: --------------------------------------------------------------------------- [2001-02-22 18:47:21] eric@lcb.uoregon.edu When I try to use the date() inside of a class in PHP4.0.4pl1 an error gets returned. Example: <? class showDate { var $dateTest = date("Y-m-d"); } $object1 = new showDate; echo $object1->dateTest; ?> Returns the following error: Parse error: parse error, expecting ','' or ';'' in /path/to/file/date_test.php on line 7 My php.ini has expose tags = off, and an include path, otherwise it's pretty much out of the box php.ini I did a static build with the following config: ./configure --with-apache=../apache --with-mysql=/path/to/mysql --with-openssl=/path/to/ssl --with-zlib --with-xml --enable-bcmath Thanks, eric --------------------------------------------------------------------------- ATTENTION! Do NOT reply to this email! To reply, use the web interface found at http://bugs.php.net/?id=9414&edit=2