PHP 4.0 Bug #9466: Eval With return doesn't work
| From: | pvzweden at caiw dot nl | Date: | Mon, 26 Feb 2001 18:32:53 +0000 |
| Subject: | PHP 4.0 Bug #9466: Eval With return doesn't work | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-47573@lists.php.net to get a copy of this message | ||
From: pvzweden@caiw.nl
Operating system: Linux
PHP version: 4.0.3pl1
PHP Bug Type: Unknown/Other Function
Bug description: Eval With return doesn't work
When i create a piece of code with eval like :
eval = "if (!isset(\$$value)) {";
eval .= " return 0; "
eval .= "}";
eval("$eval");
The return statement doesn't work.
It works with earlier versions of php. (php3).
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Edit Bug report at: http://bugs.php.net/?id=9466&edit=1