PHP 4.0 Bug #8106 Updated: array_pop problem when using against an array returned from a class

ID: 8106 Updated by: jmcastagnetto Reported By: drew@cwa.co.nz Old-Status: Analyzed Status: Closed Bug Type: Documentation problem Assigned To: Comments: Fixed in manual (CVS) Previous Comments: --------------------------------------------------------------------------- [2000-12-07 03:13:01] sniper@php.net Reclassified as documentation problem. array_pop($arr) (and array_shift($arr) ?) returns NULL in case the $arr is an empty array or it isn't an array at all. --Jani --------------------------------------------------------------------------- [2000-12-05 06:15:12] sniper@php.net If you pass a non-array to array_pop() it just displays an error message. After checking the sources for this function, it looks like it doesn't return anything in case of this error. Do you mean it should return FALSE in case of this error? (I think it should) But if you pass an empty array for array_pop() it won't return anything but will not display any error messages either which I think is the right behaviour. --Jani --------------------------------------------------------------------------- [2000-12-04 21:10:00] drew@cwa.co.nz Seems to return no TRUE value when using array_pop () on an array returned by a class. Code Example: <? class Form { function parse ($arg) { ereg("(.*)&[(.?)]", $arg, $query); return $query; } } $form = new Form; $output = $form->parse($QUERY_STRING); $number = array_pop($output); if ($number) { echo "$number exists"; } foreach ($output as $tmp) { if (($tmp)&&($tmp != $QUERY_STRING)) { echo "$tmp<Br>"; } } ?> --------------------------------------------------------------------------- ATTENTION! Do NOT reply to this email! To reply, use the web interface found at http://bugs.php.net/?id=8106&edit=2