PHP 4.0 Bug #9983 Updated: String concatination

From: Date: Mon, 26 Mar 2001 10:10:51 +0000
Subject: PHP 4.0 Bug #9983 Updated: String concatination
Groups: php.dev 
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ID: 9983 User Update by: yohgaki@dd.iij4u.or.jp Old-Status: Closed Status: Open Old-Bug Type: Scripting Engine problem Bug Type: Documentation problem Description: String concatination I read precedence list again. There is "." operator listed and has higher precedence than "?:" operator. So PHP is working as expected. I didn't see "." It was hard to see on my browser. Thanks. Anyway, I have suggestion for the manual page, so I changed status to open as "Documentation Problem". I think the manual page better to have relevant language constructs in the precedence list even if it is not a actually a operator in PHP. (Such as "()", "{}", "::", "->", unary "-","+". It seems these are not a operator in PHP, since they are not listed. Not sure though.) Only "()" is described in the section. All of them affects how expressions are evaluated in script and I think precedence for these is important as operator precedence because programmers want expressions are evaluated as expected. How about change the section title from "Operator Precedence" to "Precedence"? Then documentation can include anything that can affects expression and still have consistency with section title. It also would be nice to have a little explaination for each operator in the precedence list. Since it is ambigous if listed operator is unary or binary. For example, unary "-" should have higher precedence than binary "-". It would be obvious for most users, but it may be usuful for someone. Previous Comments: --------------------------------------------------------------------------- [2001-03-26 03:46:52] sniper@php.net Please read this manual page: http://www.php.net/manual/en/language.operators.precedence.php --Jani --------------------------------------------------------------------------- [2001-03-26 00:17:05] yohgaki@dd.iij4u.or.jp Following code, needs "()" to get expected value. $bar = true; $str = "TEST". ($bar ? 'true' : 'false') ."TEST"; Without "(" and ")", only "true" will be in $str. (PHP4.0.4pl1/Apache DSO/Linux, PHP4.0.5RC1/Apache DSO/W2K Server) If this is expected behavior in PHP, it would better to be described in the Manual. --------------------------------------------------------------------------- Full Bug description available at: http://bugs.php.net/?id=9983

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