Re: Output seems to be out of order

You are confused :) What you did is: echo expr1 . expr2; meaning echo the expr1 concatenated with expr2. Both expressions are evaluated before the concatenation occurs. so print_r(posix_uname()) is evaluated first and prints out the posix uname info. The return value is 1 for success so what you get is echo expr1 . 1; You should do: echo "posix_uname:"; print_r(posix_uname()); echo "\n\n"; Andi At 03:55 PM 4/29/2001 -0400, Scott Wolf wrote:

Here is the script I was running to get some info. <? echo "<html><head><title>System Info</title></head><body>"; echo "<pre>"; echo "posix_getpid: " . posix_getpid() . "\n\n"; echo "posix_getppid: " . posix_getppid() . "\n\n"; echo "posix_uname: " . print_r(posix_uname()) . "\n\n"; echo "posix_times: " . print_r(posix_times()) . "\n\n"; echo "</pre>"; echo "</body></html>"; ?> Here is the output. posix_getpid: 1741 posix_getppid: 1735 Array (

    [sysname] => Linux
    [nodename] => red
    [release] => 2.4.1
    [version] => #1 Tue Feb 20 11:09:36 EST 2001
    [machine] => i686

) posix_uname: 1 Array (

    [ticks] => 345752069
    [utime] => 4
    [stime] => 0
    [cutime] => 0
    [cstime] => 0

) posix_times: 1 Either I am really confused or the output is being made in the wrong order. This is the latest cvs as of 3:30 EST with Apache 1.3 on linux. -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: php-dev-unsubscribe@lists.php.net For additional commands, e-mail: php-dev-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net