Bug #11063 Updated: $var = function_returning_array(args)[0]; doesn't work
| From: | derick@php.net | Date: | Wed, 23 May 2001 21:33:23 +0000 |
| Subject: | Bug #11063 Updated: $var = function_returning_array(args)[0]; doesn't work | ||
| Groups: | php.dev | ||
| Request: | Send a blank email to php-dev+get-56542@lists.php.net to get a copy of this message | ||
ID: 11063
Updated by: derick
Reported By: jeremy@deadbeef.com
Old-Status: Open
Status: Suspended
Old-Bug Type: Scripting Engine problem
Bug Type: Feature/Change Request
Operating system:
PHP Version: 4.0.4pl1
Assigned To:
Comments:
This syntax does not make sense at all (to me). It is not present in any language AFAIK.
A function simply returns an array, and if you want to do something with that, do it later.
However, it is a valid feature request, but I don't think it wil be implemented in short time.
Changed type to Feature Request and status to Suspended.
Derick
Previous Comments:
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[2001-05-23 16:35:48] jeremy@deadbeef.com
$var = function_returning_array(args)[0];
gives an error but
$var = function_returning_array(args);
$var=$var[0];
works fine. I think that either should work.
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