Bug #9092 Updated: variables-by-references in class constructor not working

ID: 9092 Updated by: jmoore Reported By: t.stinner@billiton.de Old-Status: Duplicate Status: Closed Bug Type: Class/Object related Operating system: PHP Version: 4.0.4pl1 Assigned To: Comments: You cant pass a literal via reference. Closing report. This is in the todo for 4.1. Previous Comments: --------------------------------------------------------------------------- [2001-02-20 01:34:45] andre@php.net covered by 6343 --------------------------------------------------------------------------- [2001-02-03 19:00:05] t.stinner@billiton.de hmm, i see your point. is it possible to define a value that should be passwd by reference as optional? --------------------------------------------------------------------------- [2001-02-03 18:09:28] zak@php.net This should not work - how can you pass a literal value by reference? However, you are right about the error message - it does seem to be incorrect. --------------------------------------------------------------------------- [2001-02-03 17:53:52] t.stinner@billiton.de This code snippet: class test { function test(&$test1=false) { } } gives me Parse error - parse error, expecting `')'' on the line with the constructor (function ...) shouldn't this work (or at least return a useful error)? --------------------------------------------------------------------------- ATTENTION! Do NOT reply to this email! To reply, use the web interface found at http://bugs.php.net/?id=9092&edit=2