Bug #11555 Updated: date() format addition

ID: 11555 Updated by: cmv Reported By: martin@humany.com Status: Open Bug Type: Feature/Change Request Operating system: PHP Version: 4.0.5 Assigned To: cmv Comments: Trouble is (I suppose), some week-of-year functions consider Monday the first day of the week, and some consider Sunday. I guess two switches in date() should be done. I'll work on this. Previous Comments: --------------------------------------------------------------------------- [2001-06-20 08:53:13] derick@php.net Not closed... --------------------------------------------------------------------------- [2001-06-20 08:52:32] derick@php.net You can use the strftime function already, it's the %W modifier. But it would be useful if date would support it indeed. --------------------------------------------------------------------------- [2001-06-20 04:44:17] martin@humany.com i live in sweden, where displaying weeknumbers in calendars of any sort is common. the following code does the work, tho i'd be very happy if it could be supported to be returned from the date() function. switch(date("w",mktime(0,0,0,$mon,$daycnt+1,$year))) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $weeknumber=round((date("z", mktime(0,0,0, date("m"),date("d")+1-$daysub,date("Y")))+7)/7); if($weeknumber==53) { //some years have 53 weeks & some 52 //so we check next weeks weeknumber, if its 1 this is week 53, otherwise, this is week 1. switch(date("w",mktime(0,0,0,date("m"),date("d")+8,date("Y")))) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $tmpweeknumber=round( (date("z", mktime(0,0,0, date("m"), date("d")+8-$daysub, date("Y")))+7)/7); if($tmpweeknumber==1) $weeknumber=53; else $weeknumber=1; } --------------------------------------------------------------------------- [2001-06-19 05:41:56] martin@humany.com i live in sweden, where displaying weeknumbers in calendars of any sort is common. the following code does the work, tho i'd be very happy if it could be supported to be returned from the date() function. the algorithm is (mondaynumber+7)/7 where mondaynumber is the day of the year of the monday of the current year switch(date("w")) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $weeknumber=(date ("z", mktime(0,0,0, date("m"), date("d")-$daysub, date("Y")) )+7)/7; --------------------------------------------------------------------------- ATTENTION! Do NOT reply to this email! To reply, use the web interface found at http://bugs.php.net/?id=11555&edit=2