Bug #11937 Updated: Bug in array handling
| From: | jeroen@php.net | Date: | Sat, 07 Jul 2001 13:10:37 +0000 |
| Subject: | Bug #11937 Updated: Bug in array handling | ||
| References: | 1 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-59149@lists.php.net to get a copy of this message | ||
ID: 11937
Updated by: jeroen
Reported By: phil3k@aon.at
Old Status: Bogus
Status: Assigned
Bug Type: Unknown/Other Function
Operating System: Windows 98
PHP Version: 4.0.5
Old Assigned To:
Assigned To: jeroen
New Comment:
Should be more clear in the docs. It is only implicitely there.
Assigning to myself.
Previous Comments:
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[2001-07-06 14:52:11] phil3k@aon.at
<?php
//Two elements in an Array
$array[] = "Maria";
$array[] = "Lisa";
//just a test output
array_walk ($array, "my_print");
//and then free the first element of the array
unset ($array[0]);
function my_print ($value)
{
print $value . " ";
}
print "<br />";
//The following dump will produce:
//array(1) { [1]=> string(4) "Lisa" }
//This means that the first element has the index 1
//But it should have index 0
var_dump ($array);
?>
If you have more than two elements, and you free one of them, you can just prevent this bug, by
resorting the array with any sort function. But with only two elements, this won't work, and if
you clear the first of these, you will get the same result as I have got, there was one element,
but with the wrong index.
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