Bug #12042 Updated: $ can't be escaped when using ereg function
| From: | zak@php.net | Date: | Wed, 11 Jul 2001 09:51:51 +0000 |
| Subject: | Bug #12042 Updated: $ can't be escaped when using ereg function | ||
| References: | 1 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-59678@lists.php.net to get a copy of this message | ||
ID: 12042
Updated by: zak
Reported By: teocl@globalsources.com
Old Summary: $ can't be escaped when using ereg function
Old Status: Open
Status: Bogus
Bug Type: *Regular Expressions
Operating System: LINUX
PHP Version: 4.0.6
New Comment:
This is known and expected behavior. Please review the regex docs more carefully - also search the
php-general mailing list archives.
The quick fix is to place 3 backslashes in front of the $.
Previous Comments:
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[2001-07-11 05:46:09] teocl@globalsources.com
Please see the codes below:
<?
$arrfile = '<?include("$DOCUMENT_ROOT/TEMPLATES/TOP-BANNER.HTM");?>';
if(eregi("<\?include\(\"\$DOCUMENT_ROOT/TEMPLATES/TOP-BANNER\.HTM\"\);\?>",$arrfile))
print "good\n";
else
print "bad\n";
?>
The result will return "bad" because the eregi can't find the expression in the
$arrfile. If I removed the $, it will return "good". I guess "$" can't be
escaped inside the eregi function. Please help.
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