Bug #12880: arg_separator.output does not get used

From: Date: Tue, 21 Aug 2001 15:54:24 +0000
Subject: Bug #12880: arg_separator.output does not get used
Groups: php.dev 
Request: Send a blank email to php-dev+get-63980@lists.php.net to get a copy of this message
From: dank@cse.unsw.edu.au Operating system: Debian GNU/Linux (potato) PHP version: 4.0.6 PHP Bug Type: *Configuration Issues Bug description: arg_separator.output does not get used I set both arg_separator.output and arg_separator.input to ';' in my php.ini, and when I have a query string of the form asdf=1;qwerty=2 PHP parses it into 2 separate variables, showing that arg_sepatator.input works, but when I have PHP generate a query string (by setting the method to GET in a form) PHP would create asdf=1&qwerty=2 which it then parses into a single variable asdf (cos the input separator is ';') thanks, dan p.s. both phpinfo() and ini_get have confirmed that the options have been set correctly, so I am guessing it's a bug -- Edit bug report at: http://bugs.php.net/?id=12880&edit=1

« previous php.dev (#63980) next »