Re: preg_replace is changing the type of replacement parameter !!

This is fixed now. On Thu, 13 Sep 2001, Nicolas Guilhot wrote: > Hi guys, > > When I use preg_replace with an array of integer as the replacement > parameter, this function modifies the type of each array element to string. > I don't understand why it alters the content of the array while this > variable is not pass by reference (True or not ??). > > I have just upgraded to PHP 4.0.6 and it I don't think it was the case in > PHP 4.0.4 (the version I was using before, without this problem). > > Here is a short example that demonstrate my problem. > > <?php > $ary_pattern = array("@One@"); > $ary_replace = array(1); > $string_before = "One example"; > echo gettype($ary_replace[0]); // This line outputs 'integer' > $string_after = preg_replace($ary_pattern, $ary_replace, $string_before); > echo "<br>$string_after<br>"; > echo gettype($ary_replace[0]); // This line outputs 'string' > ?> > > Is this a bug from preg_replace or am I doing wrong somewhere? Any help > would be appreciated. > Regards. > > Nicolas Guilhot > > -- > PHP Development Mailing List <http://www.php.net/> > To unsubscribe, e-mail: php-dev-unsubscribe@lists.php.net > For additional commands, e-mail: php-dev-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net -Andrei * Black holes are where God divided by zero. *