Re: Bug #14273 Updated: When I use 'urlencode' in a for loop the mod_php core dumps'

Hello, On 29 Nov 2001 FitzpatrickB@metrocall.com wrote: > ID: 14273 > User updated by: FitzpatrickB@metrocall.com > Status: Closed Why did you close it? Derick > > > Previous Comments: > ------------------------------------------------------------------------ > > [2001-11-29 09:53:41] FitzpatrickB@metrocall.com > > var_dump($url) returns 'string(206) > "http://maps.yahoo.com/py/pmap.py?Pyt=Tmap&addr=6133 A > Backlick > Road&city=Springfield&state=VA&zipcode=22150&BFKey=&mag=9&cs=9&name=Jhoon > Rhee Institute of Tae Kwon Do&name=Concord Centre&desc=(703) 923-0052"' > > I tried > urlencode($url); > This worked... > > I then tried > $url = urlencode($url); > And this also cored! > > ------------------------------------------------------------------------ > > [2001-11-29 09:49:31] mfischer@php.net > > Its impossible to track this down with actual data which crashes this, please provide such > data. > > Feedback. > > ------------------------------------------------------------------------ > > [2001-11-29 09:47:47] FitzpatrickB@metrocall.com > > I forgot the comma in the list when I rewrote the example. I have the comma in my > 'real' code. > > ------------------------------------------------------------------------ > > [2001-11-28 17:51:47] mfischer@php.net > > Um ... list($name$url) looks really weird to me. You should write list($name, $url) instead. > > Can you reproduce this with latest (not official) release? > > http://www.php.net/~zeev/php-4.1.0.tar.gz > > Also, the actual content of '$url' would be interesting anyway (since coredump is > never ok), something like 'var_dump($url);' before passing it to urlencode(). > > Feedback. > > ------------------------------------------------------------------------ > > [2001-11-28 17:23:08] FitzpatrickB@metrocall.com > > This works!!! > > $cnt = count($arrayA); > for ( $ix=0 ; $ix < $cnt; $ix++ ) > { > $aurl = mysql_query("select name, url from sites where > code='".$arrayA[$ix][1]."'"); > list($name$url) = mysql_fetch_row($aurl); > mysql_free_result($aurl); > > echo "$url $name"; > } > > This Fails!! > $cnt = count($arrayA); > for ( $ix=0 ; $ix < $cnt; $ix++ ) > { > $aurl = mysql_query("select name, url from sites where > code='".$arrayA[$ix][1]."'"); > list($name$url) = mysql_fetch_row($aurl); > mysql_free_result($aurl); > > echo urlencode($url)," $name"; > } > > Only change is addition of urlencode, What gives? > > ------------------------------------------------------------------------ > > > > Edit this bug report at > http://bugs.php.net/?id=14273&edit=1 > > > -- > PHP Development Mailing List <http://www.php.net/> > To unsubscribe, e-mail: php-dev-unsubscribe@lists.php.net > For additional commands, e-mail: php-dev-help@lists.php.net > To contact the list administrators, e-mail: php-list-admin@lists.php.net >