Bug #11008 Updated: exit() should return an exit status if passed, not send to stdout

ID: 11008 Updated by: sniper Reported By: brianm@dealnews.com Old Status: Closed Status: Analyzed Bug Type: Scripting Engine problem Operating System: Linux PHP Version: 4.0 Latest CVS (2001-05-21) New Comment: I just got bitten by this. The manual page says that if the value passed to exit() is integer it is used as exit status. Or is there some other way to exit from PHP script with an exit status? --Jani Previous Comments: ------------------------------------------------------------------------ [2001-07-15 16:43:19] zeev@php.net Simply put - no, it should not. exit's optional argument is a termination message, not a shell status. ------------------------------------------------------------------------ [2001-05-23 11:24:22] brianlmoon@php.net Anyone in the Zend core want to comment on this? I know where the code is that does it. But it is in the Zend code. Is there a good reason to put this exit status to stdout? ------------------------------------------------------------------------ [2001-05-22 01:59:53] bbonev@php.net indeed it does both: if php; then echo yes; fi <? exit(0) ?> X-Powered-By: PHP/4.0.5 Content-type: text/html 0yes if php; then echo yes; fi <? exit(1) ?> X-Powered-By: PHP/4.0.5 Content-type: text/html 1 i don't see a real reason for the echoed exit status though ------------------------------------------------------------------------ [2001-05-21 21:34:23] brianm@dealnews.com Working with a shell script here. I hoped that exit() would work like perl and return the passed status as and exist status. As it stands now, it sends it to stdout. This is unexpected. It would be much more useful if exit() could be used to enable the use of PHP in shell scripts by returning the passed value as an exit status. ------------------------------------------------------------------------ Edit this bug report at http://bugs.php.net/?id=11008&edit=1