Bug #14992 Updated: Behaviour of $array = $array1 + $array2; not documented
| From: | andrei@php.net | Date: | Wed, 16 Jan 2002 17:53:08 +0000 |
| Subject: | Bug #14992 Updated: Behaviour of $array = $array1 + $array2; not documented | ||
| References: | 1 | Groups: | php.dev php.doc |
| Request: | Send a blank email to php-dev+get-77276@lists.php.net to get a copy of this message | ||
ID: 14992
Updated by: andrei
Reported By: mfischer@php.net
Status: Open
Bug Type: Documentation problem
PHP Version: 4.1.1
New Comment:
$array1 + $array2 is *not* the same as array_merge(). See for yourself
with array(1, 2) and array(5, 6, 7).
Previous Comments:
------------------------------------------------------------------------
[2002-01-11 06:03:44] philip@php.net
Where should this feature be documented, I see two viable options:
a) Under array_merge()
b) A new "Array Operators" man page.
I assume most people wanting to merge arrays will go to array_merge()
but having it's own man page could make room to clearly explain the
differences of it and array_merge and array_merge_recursive. I vote
for (b). Of course the functions would link to it. This is kinda like
how
backticks are documented now, as, "Execution Operators".
A brief note under "Arithmetic Operators" may be appropriate too.
Also, for those interested in documenting this beast, please see this
post:
http://marc.theaimsgroup.com/?l=phpdoc&m=101074306518514
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[2002-01-11 05:04:53] mfischer@php.net
The behaviour of the following code doens't seem to be documented:
<?
$foo = array(27 => 'Ene');
$bar = array(-1 => 'Mene');
$baz = $foo + $bar;
var_dump($baz);
?>
array(2) {
[27]=>
string(3) "Ene"
[-1]=>
string(4) "Mene"
}
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Edit this bug report at http://bugs.php.net/?id=14992&edit=1