Bug #15438 Updated: include_once fails when comparing output to a value

From: Date: Fri, 08 Feb 2002 15:51:59 +0000
Subject: Bug #15438 Updated: include_once fails when comparing output to a value
References: 1  Groups: php.dev 
Request: Send a blank email to php-dev+get-79742@lists.php.net to get a copy of this message
ID: 15438 Updated by: derick@php.net Reported By: michael@gamepoint.net -Status: Bogus +Status: Open -Bug Type: Filesystem function related +Bug Type: Scripting Engine problem Operating System: FreeBSD PHP Version: 4.1.1 New Comment: Actually you can check if an include failed or not like this, but I think the parser gets confused if you use the '== false'. Making this a scripting engine problem. Derick Previous Comments: ------------------------------------------------------------------------ [2002-02-08 09:48:32] sander@php.net RTM! You can't include_once check for succes on include/include_once. include(_once) is not a function. ------------------------------------------------------------------------ [2002-02-07 17:21:40] michael@gamepoint.net When trying to check if include_once succeeded i came up the following bug (i believe): if( include_once("test1.php") == false ) { print "Failed to include file"; } Warning: Failed opening '' for inclusion (include_path='.:/usr/local/lib/php') in /usr/home/michael/www/bug.php on line 6 Removing '== false' removes the problem. My configuration is: FreeBSD 4.5 Apache 1.3.22 PHP 4.1.1 Configure options: './configure' '--with-mysql' '--with-apxs' ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=15438&edit=1

« previous php.dev (#79742) next »