Re: sizeof foo vs sizeof (foo) (Was Re: [PHP-DEV] PHP audit)
| From: | Jedi/Sector One | Date: | Thu, 14 Mar 2002 13:34:54 +0000 |
| Subject: | Re: sizeof foo vs sizeof (foo) (Was Re: [PHP-DEV] PHP audit) | ||
| References: | 1 2 | Groups: | php.dev |
| Request: | Send a blank email to php-dev+get-81209@lists.php.net to get a copy of this message | ||
On Thu, Mar 14, 2002 at 01:19:32PM +0000, Wez Furlong wrote:
> I know of a compiler for the Amiga that doesn't grok 'sizeof struct foo';
> the solution is to always use 'sizeof(struct foo)'.
sizeof <type> is incorrect.
The correct sizeof semantics are
sizeof <value>
or:
sizeof( <type> )
So sizeof (<value>) means to evaluate '(<value>)' whoose result is
'<value>', then compute 'sizeof <value>' .
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