Bug #1673: ereg_replace doesn't handle \$var correctly

From: Date: Tue, 06 Jul 1999 21:03:49 +0000
Subject: Bug #1673: ereg_replace doesn't handle \$var correctly
Groups: php.dev 
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From: conley@enteka.com Operating system: Solaris 2.6 PHP version: 3.0.9 PHP Bug Type: Other Bug description: ereg_replace doesn't handle \$var correctly In attempting to do lame macro functionality, I found that the \$login never matches strings like: Your login is $login. Here is the suspect code: while (! feof($form)) { // Grab a line at a time doing variable substitutions on $variable $line = fgets($form,1023); $new = ereg_replace("\$login", "newvalue", $line); if ($line != $new) { print "<PRE>line=[$line]</PRE>\n"; print "<PRE>new=[$new]</PRE>\n"; } print $line; } If I change \$login to just login I find I get: Your newvalue is $newvalue. Which is correct, so I think the rest of the code is correct-- just the $ escaping is broken.

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