compiling php

Hi All, what does this mean? /bin/sh libtool --silent --mode=compile gcc -Iext/zlib/ -I/usr/local/www/php4-200208210300/ext/zlib/ -DPHP_ATOM_INC -I/ usr/local/www/php4-200208210300/include -I/usr/local/www/php4-200208210300/m ain -I/usr/local/www/php4-200208210300 -I/usr/local/www/apache2/2.0.40/include - I/us r/local/www/php4-200208210300/Zend -I/usr/local/include -I/usr/local/include /fre etype2 -I/oracle/oracode/9.2.0.1/rdbms/public -I/oracle/oracode/9.2.0.1/rdbm s/de mo -I/oracle/oracode/9.2.0.1/plsql/public -I/usr/local/www/php4-20020821030 0/TS RM -mpa-risc-2-0 -O -D_HPUX_SOURCE -prefer-pic -c /usr/local/www/php4-200208210300/ext/zlib/zlib.c -o ext/zlib/zlib.lo gcc: cannot specify -o with -c or -S and multiple compilations make: *** [ext/zlib/zlib.lo] Error 1 The configure command I ran is this: CC=gcc CFLAGS="-mpa-risc-2-0 -O -D_HPUX_SOURCE" ./configure --with-apxs2=/usr/local/www/apache2/current/bin/apxs --with-zlib -dir =/usr/local/lib/ --with-zlib --without-mysql --enable-versioning --enable-tr ack- vars=yes --enable-url-includes --enable-trans-sid --enable-sysvshm=yes --ena ble- sysvsem=yes --with-ftp --with-config-file-path=/etc --with-gd=/usr/local --w ith- png-dir=/usr/local/lib --with-jpeg-dir=/usr/local/lib --with-xpm-dir=/usr/lo cal/ lib --with-freetype-dir=/usr/local --enable-gd-native-ttf --with-gettext=/us r/lo cal --with-expat-dir=/usr/local --with-oracle=/oracle/oracode/9.2.0.1 --with -oci 8=/oracle/oracode/9.2.0.1 I tried it without the CFLAGS, I was experimenting. I'm trying to build php with Oracle 9i Release 2 (64bit) with Apache 2.0.40 on my HPUX11i box. I have editing the config.m4 files for both oci8 and oracle to point to the 32bit lib directories. What other information would be helpfull? Thanks in advance AG