Doc #68895 [Nab]: Error on parse_str() example

Edit report at https://bugs.php.net/bug.php?id=68895&edit=1 ID: 68895 User updated by: nazarenolorenzo at gmail dot com Reported by: nazarenolorenzo at gmail dot com Summary: Error on parse_str() example Status: Not a bug Type: Documentation Problem Package: Documentation problem PHP Version: Irrelevant Block user comment: N Private report: N New Comment: You're right. I was confused about how it works. Thanks for the clarification Previous Comments: ------------------------------------------------------------------------ [2015-01-23 19:20:58] aharvey@php.net It's (unfortunately) correct: if the second argument isn't given to parse_str(), it creates variables in the current scope. ------------------------------------------------------------------------ [2015-01-23 19:16:57] nazarenolorenzo at gmail dot com Description: ------------ --- From manual page: http://www.php.net/function.parse-str --- The first part of the current example prints $arr, which is never declared: <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; parse_str($str); echo $first; // value echo $arr[0]; // foo bar echo $arr[1]; // baz Expected result: ---------------- Instead, it should be: <?php $str = "first=value&arr[]=foo+bar&arr[]=baz"; $arr = parse_str($str); echo $first; // value echo $arr[0]; // foo bar echo $arr[1]; // baz ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=68895&edit=1