Doc #71800 [Opn->Nab]: string checks is_array enters into if and makes that string null

From: Date: Fri, 11 Mar 2016 12:43:35 +0000
Subject: Doc #71800 [Opn->Nab]: string checks is_array enters into if and makes that string null
References: 1  Groups: php.doc.bugs 
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Edit report at https://bugs.php.net/bug.php?id=71800&edit=1 ID: 71800 Updated by: requinix@php.net Reported by: muhammadhu dot aiman at gmail dot com Summary: string checks is_array enters into if and makes that string null -Status: Open +Status: Not a bug Type: Documentation Problem Package: Arrays related Operating System: Ubuntu 15.04 PHP Version: 5.6Git-2016-03-11 (snap) Block user comment: N Private report: N New Comment: Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Due to the volume of reports we can not explain in detail here why your report is not a bug. The support channels will be able to provide an explanation for you. Thank you for your interest in PHP. Your code is passing in an array, not a string. PHP itself did not change $str. Previous Comments: ------------------------------------------------------------------------ [2016-03-11 12:32:24] muhammadhu dot aiman at gmail dot com Description: ------------ --- From manual page: http://www.php.net/function.is-array --- although only array should become true and should enter inside the if, but strings enter into the is_array() and string is converted into null array. Test script: --------------- //a string is passed to the checkString protected function checkString($str) if(is_array($str)) { //only arrays allowed here but string goes into if var_dump($str);exit; //string enters here and $str becoumes a null array } else { echo 'ok'; } } result is array(0) { } Expected result: ---------------- protected function checkString($str) if(is_array($str)) { //only arrays allowed here but string goes into if var_dump($str);exit; //string enters here and $str becoumes a null array } else { echo 'ok'; } } result should be 'ok' Actual result: -------------- array(0) { } ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=71800&edit=1

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