Doc #75546 [Ver]: Clarification for how iterator_apply's $args are passed to the $function
| From: | ycgambo at outlook dot com | Date: | Wed, 22 Nov 2017 06:31:29 +0000 |
| Subject: | Doc #75546 [Ver]: Clarification for how iterator_apply's $args are passed to the $function | ||
| References: | 1 | Groups: | php.doc.bugs |
| Request: | Send a blank email to doc-bugs+get-15250@lists.php.net to get a copy of this message | ||
Edit report at https://bugs.php.net/bug.php?id=75546&edit=1
ID: 75546
User updated by: ycgambo at outlook dot com
Reported by: ycgambo at outlook dot com
Summary: Clarification for how iterator_apply's $args are
passed to the $function
Status: Verified
Type: Documentation Problem
Package: SPL related
Operating System: centos6
PHP Version: 5.6.32
Block user comment: N
Private report: N
New Comment:
Got it, thanks for reply.
Previous Comments:
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[2017-11-21 07:17:12] requinix@php.net
$args is an array and each of its elements are passed to the callback as separate arguments.
https://3v4l.org/6Qrnk
------------------------------------------------------------------------
[2017-11-21 06:21:38] ycgambo at outlook dot com
Description:
------------
---
From manual page: http://www.php.net/function.iterator-apply
---
the 3rd parameter
args of iterator-apply doesn't passed to callback as an array.
Test script:
---------------
<?php
$ai = new ArrayIterator(range(0, 2));
iterator_apply($ai, function($args) {
var_dump($args);
return true;
}, array(1, 2));
Expected result:
----------------
array(2) {
[0] =>
int(1)
[1] =>
int(2)
}
array(2) {
[0] =>
int(1)
[1] =>
int(2)
}
array(2) {
[0] =>
int(1)
[1] =>
int(2)
}
Actual result:
--------------
int(1)
int(1)
int(1)
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=75546&edit=1