Bug->Doc #77489 [Opn->Ver]: Yield inside IF instruction

Edit report at https://bugs.php.net/bug.php?id=77489&edit=1 ID: 77489 Updated by: cmb@php.net Reported by: hlecorche at e-commit dot fr Summary: Yield inside IF instruction -Status: Open +Status: Verified -Type: Bug +Type: Documentation Problem Package: Scripting Engine problem Operating System: Debian GNU/Linux PHP Version: 7.2.14 Block user comment: N Private report: N New Comment: The language specification clarifies this[1]: | Any function containing yield is a generator function. The PHP manual could be improved in this regard, though. [1] <https://github.com/php/php-langspec/blob/master/spec/13-functions.md#general> Previous Comments: ------------------------------------------------------------------------ [2019-01-19 10:54:10] hlecorche at e-commit dot fr Description: ------------ When a function has a YIELD instruction inside a IF instruction, the yield instruction is called even if the IF INSTRUCTION is not true. Tested whith 7.0.33, 7.1.26 and 7.2.14 versions. Test script: --------------- function gen_one_to_three($useYield = true) { $result = []; for ($i = 1; $i <= 3; $i++) { if (true === $useYield) { yield $i; } else { $result[] = $i; } } if (false === $useYield) { return $result; } } $return1 = gen_one_to_three(true); echo get_class($return1) $return2 = gen_one_to_three(false); echo get_class($return2); Expected result: ---------------- Generator PHP Warning: get_class() expects parameter 1 to be object, array given Actual result: -------------- Generator Generator ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=77489&edit=1