Doc #78163 [Opn->Ver]: preg_quote() documented as accepting null for $delimiter, which actually throws

Edit report at https://bugs.php.net/bug.php?id=78163&edit=1 ID: 78163 Updated by: cmb@php.net Reported by: sp at fp dot de Summary: preg_quote() documented as accepting null for $delimiter, which actually throws -Status: Open +Status: Verified Type: Documentation Problem Package: PCRE related PHP Version: 7.3.6 -Assigned To: +Assigned To: cmb Block user comment: N Private report: N Previous Comments: ------------------------------------------------------------------------ [2019-06-14 15:33:43] requinix@php.net Per the source, the actual default value is "\0" (which is always quoted anyways). ------------------------------------------------------------------------ [2019-06-14 15:29:53] sp at fp dot de Description: ------------ Referring to Nikitas post: https://www.mail-archive.com/internals@lists.php.net/msg98043.html > If you see something that is documented as =null, but does not behave the > same when null is passed, please do report a bug. preg_quote() seems to fall under that category: https://www.php.net/manual/en/function.preg-quote.php It is documented as: preg_quote ( string $str [, string $delimiter = NULL ] ) : string But actually passing NULL as second argument throws TypeError with strict_types=1: "Fatal error: Uncaught TypeError: preg_quote() expects parameter 2 to be string, null given" Test script: --------------- https://3v4l.org/ufjFF ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=78163&edit=1